5x^2+54x^2-405x=0

Solution for 5x^2+54x^2-405x=0 equation:

5x^2+54x^2-405x=0

We add all the numbers together, and all the variables

59x^2-405x=0

a = 59; b = -405; c = 0;
Δ = b2-4ac
Δ = -4052-4·59·0
Δ = 164025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{164025}=405$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-405)-405}{2*59}=\frac{0}{118}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-405)+405}{2*59}=\frac{810}{118}
=6+51/59
$